匿名函数：lambda
f = lambda x,y,z: x+y+z f(2,3,4) >>9
def knights():
title = 'Sir'
action = (lambda x:title+''+x)
return action
act = knights()
act('robin')
>>'Sir robin'在序列中映射函数：map
counters = [1,2,3,4] def inc(x):return x+10 list(map(inc, counters)) >>[11,12,13,14]
函数式编程工具：filter和reduce
list(filter((lambda x:x>0), ranger(-5,5))) >>[1,2,3,4]
from functools import reduce reduce((lambda x,y:x+y), [1,2,3,4]) >>10